2x^2-50=88

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Solution for 2x^2-50=88 equation:



2x^2-50=88
We move all terms to the left:
2x^2-50-(88)=0
We add all the numbers together, and all the variables
2x^2-138=0
a = 2; b = 0; c = -138;
Δ = b2-4ac
Δ = 02-4·2·(-138)
Δ = 1104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1104}=\sqrt{16*69}=\sqrt{16}*\sqrt{69}=4\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{69}}{2*2}=\frac{0-4\sqrt{69}}{4} =-\frac{4\sqrt{69}}{4} =-\sqrt{69} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{69}}{2*2}=\frac{0+4\sqrt{69}}{4} =\frac{4\sqrt{69}}{4} =\sqrt{69} $

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